WebJan 16, 2015 · You want the left (x) characters up to, but not including the first comma. You need to calculate the number of characters to grab, so you need to know the position of the comma. You could do this with a left, but substring is straightforward: BEGIN DECLARE @string VARCHAR (50); SET @string = 'CUSTOMER1,Customer Name 1, 01234 567 891'; WebMar 1, 2024 · In the below SQL query, we use the [^] string operator. It finds out the position of the character without an alphabet, number or space. 1 2 SELECT position = PATINDEX('% [^ 0-9A-z]%', 'You are a prominent author at SQLShack!'); In the below example, we use the PATINDEX () function for a table column.
SQL Server Get String Before and After Character (Delimiter) Example
WebApr 12, 2024 · Here, the WHERE clause is used to filter out a select list containing the ‘FirstName’, ‘LastName’, ‘Phone’, and ‘CompanyName’ columns from the rows that … jobs for people leaving the armed forces
Extract string before character occurrence. - SQLServerCentral
WebApr 14, 2024 · tl;dr. Use split_part which was purposely built for this:. split_part(string, '_', 1) Explanation. Quoting this PostgreSQL API docs:. SPLIT_PART() function splits a string on a specified delimiter and returns the nth substring. The 3 parameters are the string to be split, the delimiter, and the part/substring number (starting from 1) to be returned. WebTour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site WebJan 16, 2015 · Sorted by: 17 You can use the third parameter of charindex () that is used to specify where in the string the search will start. declare @S varchar (20) = '45465@6464@654'; select left (@S, charindex ('@', @S, charindex ('@', @S)+1)-1); Result 45465@6464 Share Improve this answer Follow answered Jan 16, 2015 at 13:17 Mikael … insults deliberately